We can find the value of an expression when given the values of \(x\), \(y\), etc. To find the value of an expression, we need to substitute the given values for \(x\) and \(y\) into \(3x + 5y\).

A UNSW Sydney mathematician has discovered a new method to tackle algebra's oldest challenge—solving higher polynomial equations. Polynomials are equations involving a variable raised to powers, such ...

Courtney Gibbons is affiliated with the Association for Women in Mathematics and the American Mathematical Society. You might remember learning about the quadratic formula to figure out the solutions ...

Two of the terms involve \(x\) and two involve \(y\). Now we can combine the \(x\) terms and combine the \(y\) terms to get \(3x + 2y\).

You scrambled up a Rubik's cube, and now you want to put it back in order. What sequence of moves should you make? Surprise: You can answer this question with modern algebra. Most folks who have been ...

A mathematician has built an algebraic solution to an equation that was once believed impossible to solve. The equations are fundamental to maths as well as science, where they have broad applications ...

Algebra can be demystified with the right approach. Transforming word problems into mathematical expressions is crucial, alongside using formula sheets and colour-coding equations for clarity.

For ax 2 + bx + c = 0, (α, β) = [–b ± √(b 2 – 4ac)]/2ac, where α and β are the roots of the equation. Sum of roots = –b/a Product of roots = c/a If roots of a quadratic equation are given, then the ...